A) \[{{H}_{3}}P{{O}_{3}}\]
B) \[HP{{O}_{3}}\]
C) \[{{H}_{3}}P{{O}_{2}}\]
D) \[{{H}_{3}}P{{O}_{4}}\]
Correct Answer: D
Solution :
\[PC{{l}_{5}},\], on hydrolysis, with insufficient quantity of water, gives \[POC{{l}_{3}}\] while with excess of water gives phosphoric acid, \[({{H}_{3}}P{{O}_{4}})\]. \[PC{{l}_{5}}+4{{H}_{2}}O\xrightarrow{Excess\,of\,water}{{H}_{3}}P{{O}_{4}}+5HCl\]
You need to login to perform this action.
You will be redirected in
3 sec
