A) Tollen reagent
B) Fehling solution
C) \[NaOH/{{I}_{2}}/{{H}^{+}}\]
D) \[NaOH/NaI/{{H}^{+}}\]
Correct Answer: C
Solution :
Methyl ketones when treated with \[NaOH/{{I}_{2}}/{{H}^{+}}\] give iodoform and an acid (with one carbon less than the parent ketone). \[\underset{\begin{smallmatrix} \text{butane-2-one} \\ \text{(methyl}\,\,\text{ketone)} \end{smallmatrix}}{\mathop{C{{H}_{3}}C{{H}_{2}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}}}\,+NaOH+{{I}_{2}}\xrightarrow[\begin{smallmatrix} -NaI \\ -{{H}_{2}}O \end{smallmatrix}]{}\]\[CH{{I}_{3}}+C{{H}_{3}}C{{H}_{2}}COONa\xrightarrow{{{H}^{+}}}\underset{propanoic\,\,acid}{\mathop{C{{H}_{3}}C{{H}_{2}}COOH}}\,\]
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