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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2009

  • question_answer
    47.      In a photoelectric experiment the relation between applied potential difference between              cathode and anode V and the photoelectric current \[I\] was found to be shown in graph below. If planck?s constant \[h=6.6\times {{10}^{-34}}\]J-s, the      frequency of incident radiation would be nearly                (in s-1)

    A)             \[0.436\times {{10}^{18}}\]                             

    B)             \[0.436\times {{10}^{17}}\]

    C)             \[0.775\times {{10}^{15}}\]                             

    D)             \[0.775\times {{10}^{16}}\]

    Correct Answer: C

    Solution :

    For photoelectric effect, \[e{{V}_{0}}=hv\]                 \[\Rightarrow \]               \[v=\frac{e{{V}_{0}}}{h}\]                 \[\therefore \]  \[v=\frac{1.6\times {{10}^{-19}}\times 3.2}{6.6\times {{10}^{-34}}}\]


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