A) \[\frac{ne\tau }{{{m}_{e}}}\]
B) \[\frac{n{{e}^{2}}\tau }{{{m}_{e}}}\]
C) \[\frac{n{{e}^{2}}}{\tau {{m}_{e}}}\]
D) \[\frac{{{m}_{e}}{{e}^{2}}\tau }{n}\]
Correct Answer: B
Solution :
Resistivity, \[\rho =\frac{{{m}_{e}}}{n{{e}^{2}}\tau }\] Conductivity, \[\sigma =\frac{1}{\rho }=\frac{n{{e}^{2}}\tau }{{{m}_{e}}}\]
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