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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2008

  • question_answer
    The heat of formation of \[(Co)g\] and \[C{{O}_{2}}(g)\] are \[\Delta H=-110\] and \[\Delta H=-393kJ\,\,mo{{l}^{-1}}\]respectively. What is the heat of reaction \[(\Delta H)'\] (in\[kJ\text{ }mo{{1}^{-1}}\]) for the following reaction? \[CO(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}C{{O}_{2}}(g)\]

    A)  \[-504\]                              

    B)  \[-142.5\]

    C)  \[-283\]                              

    D)  \[504\]

    Correct Answer: C

    Solution :

    \[C+\frac{1}{2}{{O}_{2}}\xrightarrow{{}}CO,\,\Delta H=-110kJ\,mo{{l}^{-1}}\]   ?.(i) \[C+{{O}_{2}}\xrightarrow{{}}C{{O}_{2}},\,\,\,\,\Delta H=-393kJ\,mo{{l}^{-1}}\] ??(ii) On subtracting Eq. (i) from Eq. (ii), we get \[CO+\frac{1}{2}{{O}_{2}}\xrightarrow{{}}C{{O}_{2}}\] \[\Delta H=393-(-110)\] \[=-283\,kJ\,\,mo{{l}^{-1}}\]


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