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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2008

  • question_answer
    If \[{{M}_{0}}\] is the mass of an oxygen isotope \[_{8}{{O}^{17}},\]\[{{M}_{P}}\] and \[{{M}_{n}}\] are the masses of a proton and a neutron, respectively, the nuclear binding energy of the isotope is

    A) \[({{M}_{0}}-8{{M}_{P}}){{c}^{2}}\]

    B) \[({{M}_{0}}-8{{M}_{P}}-9{{M}_{n}}){{c}^{2}}\]

    C) \[{{M}_{0}}{{c}^{2}}\]

    D) \[({{M}_{0}}-17{{M}_{n}}){{c}^{2}}\]

    Correct Answer: B

    Solution :

    Binding energy \[BE=({{M}_{nucleus}}-{{M}_{nucleons}}){{C}^{2}}\]                 \[=({{M}_{O}}-8{{M}_{P}}-9{{M}_{n}}){{C}^{2}}\]


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