A) \[0.40\,g\]
B) \[0.50\,g\]
C) \[0.67\,g\]
D) \[0.27\,g\]
Correct Answer: D
Solution :
Key Idea Apply first law of electrolysis during deposition of charge on an electrode through electrolysis. If m is the mass of a substance deposited or liberated at an electrode during electrolysis when a charge q passes through electrolyte, then according to Faraday's first law of electrolysis, \[m\propto q\] or \[m=zq\] where z is a constant of proportionality and is called electrochemical equivalent (ECE) of the the substance. If an electric current I flows through the electrolyte, then \[q=It\] \[\therefore \] \[m=zit\] Here, \[i=1.5A,\] \[t=10\min =10\times 60s,\] \[z=30\times {{10}^{-5}}g{{C}^{-1}}\] Hence, mass of copper deposited on the electrode \[m=30\times {{10}^{-5}}\times 1.5\times 10\times 60\] \[=27\times {{10}^{-2}}=0.27g\]
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