A) ethyl iodide
B) ethanol
C) iodoform
D) methyl iodide
Correct Answer: A
Solution :
Diethyl ether on heating with concentrated \[HI\]to give ethyl iodide. \[\underset{diethyl\,ether}{\mathop{{{C}_{2}}{{H}_{5}}-O-{{C}_{2}}{{H}_{5}}+2HI}}\,\xrightarrow{{}}\underset{ethyl\,\,iodide}{\mathop{2{{C}_{2}}{{H}_{5}}I}}\,+{{H}_{2}}O\]
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