Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2007

  • question_answer
    A compound has the empirical formula \[C{{H}_{2}}O\]. Its vapour density is 30. Its molecular formula is

    A)  \[{{C}_{2}}{{H}_{4}}{{O}_{2}}\]                 

    B)  \[{{C}_{2}}{{H}_{6}}O\]

    C)  \[{{C}_{2}}{{H}_{6}}{{O}_{2}}\]                 

    D)  \[{{C}_{2}}{{H}_{4}}O\]

    Correct Answer: A

    Solution :

    \[2\times \]vapour density = molecular weight \[2\times 30=60\] \[\therefore \] Molecular weight of compound = 60 (Empirical formula) \[\times n=\] molecular formula                 \[(12+1\times 2+16)\times n=60\] \[\therefore \]\[n=2\] so, \[(C{{H}_{2}}O)\times 2=\] molecular formula \[\therefore \]Molecular formula \[={{C}_{2}}{{H}_{4}}{{O}_{2}}\]


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