Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2007

  • question_answer
    A coil has 25 turns and 10 cm radius. If it carries a 4 A current, then magnetic field at its centre is

    A) \[6.28\times {{10}^{-5}}\text{T}\]                            

    B)  \[6.28\times {{10}^{-3}}\text{T}\]

    C)  \[6.28\times {{10}^{-4}}\text{T}\]                           

    D)  \[6.28\times {{10}^{-2}}\text{T}\]

    Correct Answer: C

    Solution :

    Given, \[n=25,\]\[r=10cm=0.1m,\] \[I=4A\] Magnetic field at the centre of the coil. \[B=\frac{{{\mu }_{0}}nI}{2r}\] s\[=\frac{4\pi \times {{10}^{-7}}\times 25\times 4}{2\times 0.1}\] \[=2\times 3.14\times {{10}^{-4}}=6.28\times {{10}^{-4}}T\]


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