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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2007

  • question_answer
    A torch battery consisting of two cells of 1.45 V and an internal resistance 0.15\[\Omega \] each cell sending currents through the filament of the lamps having resistance 1.5 \[\Omega .\] The value of current will be.

    A)  16.11 A                               

    B)  1.611 A

    C)  0.1611 A                             

    D)  2.6 A

    Correct Answer: B

    Solution :

    Total emf \[~=2\times 1.45=2.90\text{ }V\] Total internal resistance of the cells                 \[0.15+0.15=0.30\Omega \] Current in the filament \[(I)=\frac{E}{R+r}\]                                                 \[=\frac{2.90}{1.5+0.30}\]                                                 \[1.611A\]


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