Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2007

  • question_answer
    The current relationship between two current gains a and \[\text{ }\!\!\beta\!\!\text{ }\] in a transistor is

    A) \[\text{ }\!\!\beta\!\!\text{ }\,\text{=}\,\frac{a}{1+a}\]               

    B) \[\text{ }\!\!\beta\!\!\text{ }\,\text{=}\,\frac{a+1}{a}\]

    C) \[a\,\text{=}\,\frac{\text{ }\!\!\beta\!\!\text{ }}{a+\text{ }\!\!\beta\!\!\text{ }}\]                          

    D) \[\,\text{ }\!\!\beta\!\!\text{ =}\,\frac{\text{ }\!\!\beta\!\!\text{ +1}}{\text{ }\!\!\beta\!\!\text{ }}\]

    Correct Answer: C

    Solution :

    Relation between \[\alpha \] and \[\beta \] is given by \[\beta =\frac{\alpha }{1-\alpha }\]                 \[\Rightarrow \]               \[\beta (1-\alpha )=\alpha \]                                 \[\beta -\beta \alpha =\alpha \]                                 \[\beta =\alpha (1+\beta )\]                 or            \[\alpha =\left( \frac{\beta }{1+\beta } \right)\]


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