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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2007

  • question_answer
    A semiconductor has an electron concentration density of\[8\times {{10}^{14}}\text{/c}{{\text{m}}^{\text{3}}}\] and that of holes is \[5\times {{10}^{12}}\text{/c}{{\text{m}}^{\text{3}}}\text{.}\] The semiconductor is

    A)  n-type                                

    B)  p-type

    C)  intrinsic                              

    D)  p-n-p type

    Correct Answer: A

    Solution :

    \[{{n}_{e}}=8\times {{10}^{14}}/c{{m}^{3}}\] \[{{n}_{h}}=5\times {{10}^{12}}/c{{m}^{3}}\] As               \[{{n}_{e}}>{{n}_{h}}\] Therefore, the given semiconductor is a n-type semiconductor.


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