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  3. Chhattisgarh PMT

Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2007

  • question_answer
    If half-life of a radioactive atom is 2.3 days, then its decay constant would be

    A)  0.1                                        

    B)  0.2

    C)  0.3                                        

    D)  2.3

    Correct Answer: C

    Solution :

    Decay constant \[(\lambda )=\frac{0.693}{{{T}_{1/2}}}=\frac{0.693}{2.3}=0.3\]


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