A) 1200 J/cycle
B) 1600 J/cycle
C) 1400 J/cycle
D) None of the above
Correct Answer: B
Solution :
Given, \[{{T}_{1}}=600K,\]\[{{T}_{2}}=300K\] \[W=800J,\] \[Q=?\] Efficiency of heat engine \[(\eta )=1-\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{work\,done}{heat\,taken}\] \[1-\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{W}{Q}\] \[1-\frac{300}{600}=\frac{800}{Q}\] \[\frac{1}{2}=\frac{800}{Q}\] \[Q=1600J/cycle\]
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