Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2006

  • question_answer
    Total number of isomers of \[{{C}_{4}}{{H}_{10}}O\] is

    A) \[7\]                                     

    B) \[4\]

    C) \[3\]                                     

    D) \[8\]

    Correct Answer: A

    Solution :

    Isomers of compound having molecular formula \[{{C}_{4}}{{H}_{10}}O\] (i) \[\underset{1-\text{butanol}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-OH}}\,\] (ii) \[\underset{2-butnol}{\mathop{C{{H}_{3}}-C{{H}_{2}}-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{3}}}}\,\] (iii) \[\underset{2-methyl\,\,2-propanol}{\mathop{C{{H}_{3}}-\underset{OH}{\mathop{\underset{|}{\mathop{\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-C{{H}_{3}}}}\,\] (iv) \[\underset{2-methyl\,\,1-propanol}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{\overset{H}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-C{{H}_{2}}-OH}}\,\] (v) \[\underset{1-methoxy\,propane}{\mathop{C{{H}_{3}}-O-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}}}\,\] (vi) \[\underset{1-ethoxy\,\,ethane}{\mathop{C{{H}_{3}}-C{{H}_{2}}-O-C{{H}_{2}}-C{{H}_{3}}}}\,\] (vii) \[\underset{1-methoxy\,1-methyl\,ethane}{\mathop{C{{H}_{3}}-O-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{\overset{H}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-C{{H}_{3}}}}\,\]


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