A) \[\frac{n}{N}s\]
B) \[\frac{N}{n}s\]
C) \[\frac{0.693N}{n}s\]
D) \[\frac{0.693n}{N}s\]
Correct Answer: C
Solution :
From radioactive decay law, \[\frac{dN}{dt}=-\lambda N\] But given, \[\frac{dN}{dt}=-n\] \[\therefore \] \[-n=-\lambda N\] or \[\frac{1}{\lambda }=\frac{N}{n}\] Half-life period \[(T)=\frac{0.693}{\lambda }\] ?..(i) \[=0.693\frac{N}{n}s.\]
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