question_answer

The equivalent capacitance of the circuit will be

A)  \[1.\mu F\]                                       

B)  \[3\mu F\]

C)  \[9\mu F\]                                        

D)  \[4\mu F\]

Correct Answer: A

Solution :

Capacitors of capacitances \[1.5\mu F\]and \[1.5\mu F\]are in parallel, therefore their resultant capacitance, \[C'={{C}_{1}}+{{C}_{2}}=1.5+1.5=3.0\mu F\] Now, all three capacitors are in series therefore, their resultant capacitance C will be given by                 \[\frac{1}{C}=\frac{1}{3}+\frac{1}{3}+\frac{1}{3}=\frac{3}{3}\]                 \[C=1\mu F\]