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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2005

  • question_answer
    An AC generator produced an output voltage e = 170 sin 377 t volt, where t is in second. The frequency of AC voltage is

    A)  50 Hz                                   

    B)  110 Hz

    C)  60 Hz                                   

    D)  230 Hz

    Correct Answer: C

    Solution :

    Given voltage   equation  \[e=170\sin \,377t\] Compare it with \[e={{\varepsilon }_{0}}\,\,\sin \,\omega t,\] we get \[\therefore \] Frequency \[f=\frac{377}{2\pi }=60Hz\]


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