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  3. Chhattisgarh PMT

Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2005

  • question_answer
    Two plates are 2 cm apart, a potential difference of 10 V is applied between them, the electric field between the plates is

    A)  20N/C                                 

    B)  500 N/C

    C)  5 N/C                                   

    D)  250 N/C

    Correct Answer: B

    Solution :

    Electric field between the plates \[E=\frac{V}{d}=\frac{10}{2\times {{10}^{-2}}}\] \[=500N/C\]


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