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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2005

  • question_answer
    A short bar magnet placed with its axis at \[30{}^\circ \] with a uniform external magnetic field of 0.16 T experiences a torque of magnitude 0.032 J. The magnetic moment of the bar magnet will be

    A)  0.23 J/T                               

    B)  0.40 J/T

    C)  0.80 J/T                               

    D)  zero

    Correct Answer: B

    Solution :

    As   \[\tau =MB\,\,\sin \theta \] \[\Rightarrow \]               \[M=\frac{\tau }{B\,\sin \,\theta }\]                 \[=\frac{0.032}{0.16\times \sin \,{{30}^{o}}}=0.40J/T\]


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