Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2005

  • question_answer
    The value of Faraday constant is

    A) \[9.65\times {{10}^{4}}C\]                           

    B) \[9.65\times {{10}^{4}}\text{J}\]

    C) \[6.03\times {{10}^{27}}\text{J}\]                            

    D) \[1.6\times {{10}^{-19}}C\]

    Correct Answer: A

    Solution :

    Faraday constant \[F=Ne\] \[F=6.023\times {{10}^{23}}\times 1.6\times {{10}^{-19}}C=96368C\] \[=9.65\times {{10}^{4}}C\]


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