A) Resistivity of electrolytes decreases on increasing temperature
B) Resistance of mercury falls on decreasing its temperature
C) When joined in series a 40 W bulb glows more than a 60W bulb
D) Resistance of 40 W bulb is less than the resistance of 60 W bulb
Correct Answer: D
Solution :
Power of bulb \[P=\frac{{{V}^{2}}}{R}\] or \[R=\frac{{{V}^{2}}}{P}\] \[\Rightarrow \] \[R\propto \frac{1}{P}\] It means that the bulb with low power has large resistance. So, \[40\text{ }W\]bulb will have more resistance then \[60\text{ }W\] bulb.
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