A) becomes two times
B) becomes half
C) does not change
D) becomes one-fourth
Correct Answer: C
Solution :
Drift velocity \[{{v}_{d}}=\frac{I}{neA}\] \[\because \] Specific resistance \[\rho =\frac{RA}{l}\] or \[A=\frac{\rho l}{R}\] \[\therefore \] \[{{v}_{d}}=\frac{IR}{ne\rho l}\] Thus, \[{{v}_{d}}\] is independent of diameter of wire. Hence, drift velocity will not change.
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