Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2005

  • question_answer
    n identical condensers are joined in parallel and are charged to potential V. Now, they are separated and joined in series. Then, the total energy and potential difference of the combination will be

    A)  energy remain the same and potential difference is also same

    B)  energy remain the same and potential difference is \[nV\]

    C)  energy increases n times and potential difference remains is \[nV\]

    D)  energy increases n times and potential difference remains same

    Correct Answer: B

    Solution :

    Energy will remain same which is \[U=\frac{n.C\,{{V}^{2}}}{2}\]                 or            \[U=n\left( \frac{{{Q}^{2}}}{2C} \right)\] Potential difference \[={{V}_{1}}+{{V}_{2}}+{{V}_{3}}....{{V}_{n}}\]                                                 \[=nV\] (\[\therefore \]\[{{V}_{1}}={{V}_{2}}={{V}_{3}}....=V\])


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