Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2005

  • question_answer
      The permittivity and permeability of vacuum are \[{{\varepsilon }_{0}}\] and \[{{\mu }_{0}}\] respectively. The corresponding quantities for a medium are \[\varepsilon \] and\[\mu .\] Refractive index of a medium is

    A) \[\sqrt{\frac{\mu \varepsilon }{\mu {{  }_{0}}{{\varepsilon }_{0}}}}\]                   

    B) \[\frac{\mu {{  }_{0}}{{\varepsilon }_{0}}}{\sqrt{\mu \varepsilon }}\]

    C) \[\frac{\sqrt{\mu {{  }_{0}}{{\varepsilon }_{0}}}}{\mu   \varepsilon }\]                              

    D) \[\sqrt{\frac{\mu {{  }_{0}}{{\varepsilon }_{0}}}{\mu   \varepsilon }}\]

    Correct Answer: A

    Solution :

    Speed in medium \[{{c}_{M}}=\frac{1}{\sqrt{\mu \varepsilon }}\] Speed in vacuum \[\mu =\frac{{{c}_{0}}}{{{c}_{M}}}=\sqrt{\frac{\mu \varepsilon }{{{\mu }_{0}}{{\varepsilon }_{0}}}}\] \[\therefore \] Refractive index \[\mu =\frac{{{c}_{o}}}{{{c}_{M}}}=\sqrt{\frac{\mu \varepsilon }{{{\mu }_{0}}{{\varepsilon }_{0}}}}\]                                 \[=\sqrt{\frac{\mu \varepsilon }{{{\mu }_{0}}{{\varepsilon }_{0}}}}\]


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