A) the total translation kinetic energy of all the molecules in unit volume
B) the total kinetic energy of all the molecules in unit volume
C) two thirds of the total translational kinetic energy of all the molecules in unit volume
D) two-thirds of the total kinetic energy of all the molecules in unit volume
Correct Answer: C
Solution :
\[P=\frac{mN\,{{{\bar{c}}}^{2}}}{3V}=\frac{2}{3}.\frac{1}{2}\frac{M\,{{{\bar{c}}}^{2}}}{V}\]\[=\frac{2}{3}\left( \frac{1}{2}\rho {{{\bar{c}}}^{2}} \right)\]or \[P=\frac{2}{3}E\]
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