2. Solved Papers
  3. Chhattisgarh PMT

Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2005

  • question_answer
    The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration \[a\] is 3 : 2. The value of \[a\] is (g = acceleration due to gravity of the earth)

    A)  3/2 g                                    

    B)  g/3

    C)  2/3 g                                    

    D)  g

    Correct Answer: B

    Solution :

    According to the question \[\frac{{{W}_{1}}}{{{W}_{2}}}=\frac{mg}{m(g-a)}=\frac{3}{2}\]                 or            \[\frac{g}{g-a}=\frac{3}{2}\]                 \[\Rightarrow \]               \[a=\frac{g}{3}m/{{s}^{2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner