A) \[\text{ }\!\![\!\!\text{ }{{\text{M}}^{\text{0}}}{{\text{L}}^{\text{0}}}{{\text{T}}^{\text{0}}}\text{ }\!\!]\!\!\text{ }\]
B) \[\text{ }\!\![\!\!\text{ M}{{\text{L}}^{2}}{{\text{T}}^{\text{-1}}}\text{ }\!\!]\!\!\text{ }\]
C) \[\text{ }\!\![\!\!\text{ M}{{\text{L}}^{2}}{{\text{T}}^{\text{-2}}}\text{ }\!\!]\!\!\text{ }\]
D) \[\text{ }\!\![\!\!\text{ M}{{\text{L}}^{2}}{{\text{T}}^{\text{-3}}}\text{ }\!\!]\!\!\text{ }\]
Correct Answer: B
Solution :
\[E=hv\] or \[h=\frac{E}{v}\] So, dimensions of \[h=\frac{\text{dimensions}\,of\,E}{Dimensions\,of\,v}\] \[=\frac{[M{{L}^{2}}{{T}^{-2}}]}{[{{M}^{0}}{{L}^{0}}{{T}^{-1}}]}=[M{{L}^{2}}{{T}^{-1}}]\]
You need to login to perform this action.
You will be redirected in
3 sec
