A) \[Na>Mg>Al~\]
B) \[Mg>Na>Al\]
C) \[Al>Mg>Na~\]
D) \[Mg>Al>Na\]
Correct Answer: D
Solution :
The correct sequence of elements in decreasing order of first ionisation energy is\[Mg>Al>Na\]. Ionisation potential of II A elements is higher than the ionisation potential of III A elements because II A elements has fully filled s orbitals.
You need to login to perform this action.
You will be redirected in
3 sec
