A) Tetrahedron
B) Octahedron
C) Linear
D) Plane triangle
Correct Answer: A
Solution :
The arrangement of \[s{{p}^{3}}\] hybrid orbitals is tetrahedral \[({{109}^{o}},28')\].| Type of hybridisation | Geometry of hybrid orbitals | Bond angle |
| \[sp\] | Linear | \[{{180}^{o}}\] |
| \[s{{p}^{2}}\] | Planar triangular | \[{{120}^{o}}\] |
| \[s{{p}^{3}}\] | Tetrahedral | \[{{109}^{o}}{{28}^{o}}\] |
| \[s{{p}^{3}}d\] | Trigonal bipyramidal | |
| \[s{{p}^{3}}{{d}^{2}}\] | Octahedral | \[{{90}^{o}}\] |
| \[s{{p}^{3}}{{d}^{3}}\] | Pentagonal bipyramidal |
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