question_answer

Directed bonds in water form an angle of

A)  \[{{90}^{o}}\]                                   

B)  \[{{120}^{o}}\]

C)  \[{{104.5}^{o}}\]                             

D)  \[{{60}^{o}}\]

Correct Answer: C

Solution :

Oxygen atom is present in \[s{{p}^{3}}\] hybridisation state in \[{{H}_{2}}O\] molecule. Geometry of water molecule is V-shaped, not tetrahedral because only two bonds are formed. Two hybrid orbitals do not form bond. Due to the presence of two lone pair of electrons on the oxygen atoms \[H-O-H\]bond angle is \[{{104.5}^{o}}\]\[({{105}^{o}})\] and not \[{{109}^{o}}\,{{28}^{'}}\].