question_answer

The electronic configuration of metal M is \[1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{1}},\]The formula of its oxide will be

A)  \[MO\]                               

B)  \[{{M}_{2}}O\]

C)  \[{{M}_{2}}{{O}_{3}}\]                                 

D)  \[M{{O}_{2}}\]

Correct Answer: B

Solution :

The electronic configuration of a metal (M) is \[=1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{1}},\]so valency of metal (M) is 1. Valency of oxygen \[=2\]    or                \[\therefore \] The formula of metal oxide is \[{{M}_{2}}O\].