A) \[\frac{h}{mv}=p\]
B) \[\lambda =\frac{h}{mv}\]
C) \[\lambda =\frac{h}{mp}\]
D) \[\lambda m=\frac{v}{p}\]
Correct Answer: B
Solution :
French scientist de-Broglie suggest that a moving small particle (like electron, proton etc.) has the properties of a wave. wavelength \[(\lambda )\] of the moving particle ma calculated from the following equation \[\lambda =\frac{h}{mv}\] \[\lambda =\frac{h}{p}\] [ \[\because \] \[p=mv\]] where, m = mass, v = velocity \[\lambda \] = wavelength of the moving particle P or mv = the momentum of the particle.
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