A) \[\mathbf{\vec{F}}=q\mathbf{\vec{E}}\]
B) \[\mathbf{\vec{F}}=q(\mathbf{\vec{V}}\times \mathbf{\vec{B}})\]
C) \[\mathbf{\vec{F}}=q\mathbf{\vec{E}}+q(\mathbf{\vec{V}}\times \mathbf{\vec{B}})\]
D) \[\mathbf{\vec{F}}=q\mathbf{\vec{E}}+q(\mathbf{\vec{B}}\times \mathbf{\vec{V}})\]
Correct Answer: C
Solution :
Lorentz force for a moving charged particle is \[\vec{F}=q\vec{E}+qvB\,\sin \theta \] = \[\underset{\begin{smallmatrix} Electric \\ force \end{smallmatrix}}{\mathop{q\,\vec{E}}}\,\,\,\,+\,\,\,\,\,\underset{\begin{smallmatrix} Magnetic \\ force \end{smallmatrix}}{\mathop{q(\vec{v}\times \vec{B})}}\,\]
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