A) \[11.11\,\Omega \]
B) \[9.9\,\Omega \]
C) \[1.1\,\Omega \]
D) \[4.4\,\Omega \]
Correct Answer: A
Solution :
Given, \[G=100\Omega ,\] \[{{I}_{g}}=10\times {{10}^{-3}}A,\] \[I=100\times {{10}^{-3}}A\] \[S=?\] \[\therefore \] Shunt \[S=\frac{{{I}_{g}}G}{I-{{I}_{g}}}\] \[=\frac{10\times {{10}^{-3}}\times 100}{(100-10)\times {{10}^{-3}}}\] \[=11.11\Omega \] Shunt is to be connected in parallel with the galvanometer.
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