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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2004

  • question_answer
    In a neon discharge tube\[2.9\times {{10}^{18}}\] Ne ions move to the right each second, while\[1.2\times {{10}^{18}}\] electrons move to the left per sec, electron charge is \[1.6\times {{10}^{-19}}C.\] The current in the discharge tube is

    A)  1 A towards right            

    B)  0.66 A towards right

    C)  0.66 A towards left

    D)  zero

    Correct Answer: B

    Solution :

    In the two cases current is flowing in the right direction, therefore total current \[I={{I}_{N{{e}^{+}}}}+{{I}_{e}}\]                 or            \[I=({{N}_{N{{e}^{+}}}}+{{N}_{e}})e\]                 or            \[I=(2.9\times {{10}^{18}}+1.2\times {{10}^{18}})\times 1.6\times {{10}^{-19}}\]                 \[\Rightarrow \]               \[I=0.66A\] A towards right


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