Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2004

  • question_answer
    The ratio of forward biased to reverse biased resistance for p-n junction diode is

    A)  10-1 :1                                  

    B)  10-2:1

    C)  10-3 :1                                  

    D)  10-2 : 1

    Correct Answer: D

    Solution :

    Resistance of forward bias p-n junction \[{{R}_{f}}={{10}^{2}}\Omega \]                    ...(i) Resistance of reverse bias p-n junction \[{{R}_{r}}={{10}^{6}}\Omega \]                   ...(ii) So, from Eqs. (i) and (ii)                 \[\frac{{{R}_{f}}}{{{R}_{r}}}=\frac{{{10}^{2}}}{{{10}^{6}}}=\frac{{{10}^{-4}}}{1}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner