A) Whole
B) Half
C) One-fourth
D) Three-fourth
Correct Answer: D
Solution :
Amount of radioactive material left after two half-lives \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{2T/T}}=\frac{{{N}_{0}}}{4}\] \[\therefore \] Radioactive material decayed \[={{N}_{0}}-\frac{{{N}_{0}}}{4}=\frac{3}{4}{{N}_{0}}\] Thus, three-fourth part of the radioactive material will get disintegrated after two half-lives.
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