question_answer

A particle is executing simple harmonic motion with frequency\[f.\] The frequency at which its kinetic energy changes into potential energy is

A)  \[f\text{/2}\]                                   

B)  \[f\]

C)  \[2f\]                                   

D)  \[4f\]

Correct Answer: C

Solution :

KE changes to PE from 0 to A and 0 to B. Clearly for a complete vibration, KE change m PE 2 times                                  So, the required frequency                 \[=2\times \] (frequency of SHM) \[=2f\]