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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2004

  • question_answer
    A body of mass 10 kg is moving with a constant velocity of 10 m/s. When a constant force acts for 4 s on it, it moves with a velocity 2 m/s in the opposite direction. The acceleration produced in it is

    A)  3 m/s2                                 

    B)  - 3 m/s2

    C)  0.3 m/s2                             

    D)  - 0.3 m/s2

    Correct Answer: B

    Solution :

    Given, \[m=10kg,\] \[u=10m/s,\] \[t=4s\]                 \[v=-2m/s\] By           \[v=u+at\]                 \[-2=10+a\times 4\] \[\Rightarrow \]               \[a=-3m/{{s}^{2}}\]


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