A) 8m/s
B) 6 m/s
C) 10 m/s
D) 100 m/s
Correct Answer: C
Solution :
Given, horizontal distance \[x=6t\,m\] vertical distance \[y=8t-5{{t}^{2}}m\] \[\therefore \] Horizontal velocity \[{{v}_{x}}=\frac{dx}{dt}=6m/s\] Vertical velocity \[{{v}_{y}}=\frac{dy}{dt}=8-10t\,m/s\] at \[t=0,\] \[{{v}_{y}}=8m/s\] Therefore, resultant velocity \[v=\sqrt{v_{x}^{2}+v_{y}^{2}}\] \[=\sqrt{{{6}^{2}}+{{8}^{2}}}\] \[=10m/s\]
You need to login to perform this action.
You will be redirected in
3 sec
