A) Angular momentum and Planck's constant
B) Moment of inertia and moment of force
C) Work and torque
D) Impulse and momentum
Correct Answer: B
Solution :
Moment of inertia \[I=\Sigma m{{r}^{2}}\] \[\therefore \] dimensions of \[I=[M{{L}^{2}}{{T}^{0}}]\] and moment of force \[\tau =force\] \[\times \](perpendicular distance) \[\therefore \] dimensions of \[\tau =[ML{{T}^{-2}}L]=[M{{L}^{2}}{{T}^{-2}}]\] Clearly \[I\] and \[\tau \] does not have identical dimensions.
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