CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2011

  • question_answer
    In the series L-C-R circuit shown, the impedance is

    A)  \[200\,\Omega \]                           

    B)  \[100\,\Omega \]

    C)  \[300\,\Omega \]                           

    D)  \[500\,\Omega \]

    Correct Answer: D

    Solution :

                    \[{{X}_{L}}=2\pi fL\]                 \[=2\pi \left( \frac{50}{\pi } \right)\times 1=100\Omega \] \[{{X}_{C}}=\frac{1}{2\pi fC}=\frac{1}{2\pi \left( \frac{50}{\pi } \right)20\times {{10}^{-6}}}=500\Omega \] Impedance, \[Z=\sqrt{{{R}^{2}}+{{({{X}_{C}}-{{X}_{L}})}^{2}}}\]                 \[Z=\sqrt{{{(300)}^{2}}-{{(400)}^{2}}}=500\,\Omega \]


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