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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2011

  • question_answer
    A current of \[\left( \frac{2}{\sqrt{3}} \right)A\], produces a deflection of \[{{60}^{o}}\] in a tangent galvanometer. The reduction factor is

    A)  \[\left( \frac{2}{\sqrt{3}} \right)A\]                        

    B)  \[\left( \frac{2}{3} \right)A\]

    C)  2 A                                       

    D)  \[\left( \frac{3}{2} \right)A\]

    Correct Answer: B

    Solution :

    For tangent galvanometer                 \[I=K\tan \theta \]                 \[K=\frac{I}{\tan \theta }\]                 \[K=\frac{2/\sqrt{3}}{\tan {{60}^{o}}}\]                 \[K=\frac{2}{3}A\]


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