CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2011

  • question_answer
    The critical angle of a certain medium is\[si{{n}^{-1}}\left( \frac{3}{5} \right)\]. The polarizing angle of the medium is

    A)  \[{{\sin }^{-1}}\left( \frac{4}{5} \right)\]                               

    B)  \[ta{{n}^{-1}}\left( \frac{5}{3} \right)\]

    C)  \[{{\tan }^{-1}}\left( \frac{3}{4} \right)\]                              

    D)  \[{{\tan }^{-1}}\left( \frac{4}{3} \right)\]

    Correct Answer: B

    Solution :

    Palarising angle,                 \[\tan i=\frac{1}{\sin C}\] \[\therefore \]  \[\cot i=\sin \left( {{\sin }^{-1}}\left( \frac{3}{5} \right) \right)\] or            \[\tan i=\frac{5}{3}\] or            \[i={{\tan }^{-1}}\left( \frac{5}{3} \right)\]


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