A) \[{{0}^{o}}\]
B) \[{{30}^{o}}\]
C) \[{{60}^{o}}\]
D) \[{{45}^{o}}\]
Correct Answer: D
Solution :
At second surface, there is no refraction so \[{{r}_{2}}=0\] \[\therefore \] \[{{r}_{1}}=A={{30}^{o}}\] From Snell?s law \[n=\frac{\sin {{i}_{1}}}{\sin {{r}_{1}}}\] \[n=\frac{\sin {{i}_{1}}}{\sin {{30}^{o}}}\] \[\sin {{i}_{1}}=\sqrt{2}\times \frac{1}{2}=\frac{1}{\sqrt{2}}\] \[\sin {{i}_{1}}=\frac{1}{\sqrt{2}}\] \[{{i}_{1}}={{45}^{o}}\]
You need to login to perform this action.
You will be redirected in
3 sec
