A) \[{{600}^{o}}C\]
B) \[{{327}^{o}}C\]
C) \[{{54}^{o}}C\]
D) \[{{300}^{o}}C\]
Correct Answer: D
Solution :
We know for perfect gas \[V\propto T\] Here, \[\frac{{{V}_{1}}}{{{V}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\] ... (i) According to question, \[{{V}_{1}}=V\]then \[{{V}_{2}}=2V\] and \[{{T}_{1}}=300\text{ }K\] \[\therefore \] \[\frac{1}{2}=\frac{300}{{{T}_{2}}}\] \[{{T}_{2}}=600\,K\] \[{{T}_{2}}={{327}^{o}}C\] So, \[\Delta t=327-27={{300}^{o}}C\]
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