CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2011

  • question_answer
    The displacement-time graph of two moving particles make angles of \[{{30}^{o}}\] and \[{{45}^{o}}\] with the X-axis. The ratio of their velocities is

    A)  \[\sqrt{3}:2\]                                   

    B)  \[1:1\]

    C)  \[1:2\]                                 

    D)  \[1:\sqrt{3}\]

    Correct Answer: D

    Solution :

    By the definition, the slope of displacement-time graph is velocity. \[i.e.,\] \[v=\tan \theta \] \[\therefore \]  \[\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{\tan {{\theta }_{1}}}{\tan {{\theta }_{2}}}\]                 \[\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{\tan {{30}^{o}}}{\tan {{45}^{o}}}\]                 \[\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{1}{\sqrt{3}}\]


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