CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2010

  • question_answer
    Equation of the circle centred at \[(4,3)\] touching the circle \[{{x}^{2}}+{{y}^{2}}=1\]externally, is

    A) \[{{x}^{2}}+{{y}^{2}}-8x-6y+9=0\]

    B) \[{{x}^{2}}+{{y}^{2}}+8x+6y+9=0\]

    C) \[{{x}^{2}}+{{y}^{2}}+8x-6y+9=0\]

    D) \[{{x}^{2}}+{{y}^{2}}-8x6y+9=0\]

    Correct Answer: A

    Solution :

    Given that, equation of circle \[{{x}^{2}}+{{y}^{2}}=1\]


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